ENOB relates to measured ADC performance by equating the measured SNR to that of an ideal N-bit ADC. Which statement best expresses ENOB?

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Multiple Choice

ENOB relates to measured ADC performance by equating the measured SNR to that of an ideal N-bit ADC. Which statement best expresses ENOB?

Explanation:
ENOB expresses the number of bits of an ideal ADC that would give the same signal-to-noise-plus-distortion level as the real converter. In practice you measure the ADC’s SNR for a known input (often a full-scale sine) and then map that SNR to an equivalent bit count using the relation for an ideal N-bit ADC: ENOB ≈ (SNR_meas_dB − 1.76) / 6.02. This shows the effective resolution after accounting for all noise and distortion, which may be higher or lower than the physical bit depth and can be a non-integer. ENOB is not a measure of actual architecture bits, nor of distortion-to-signal energy alone, nor of input bandwidth.

ENOB expresses the number of bits of an ideal ADC that would give the same signal-to-noise-plus-distortion level as the real converter. In practice you measure the ADC’s SNR for a known input (often a full-scale sine) and then map that SNR to an equivalent bit count using the relation for an ideal N-bit ADC: ENOB ≈ (SNR_meas_dB − 1.76) / 6.02. This shows the effective resolution after accounting for all noise and distortion, which may be higher or lower than the physical bit depth and can be a non-integer. ENOB is not a measure of actual architecture bits, nor of distortion-to-signal energy alone, nor of input bandwidth.

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